Express 20.22 in fraction form

Answer:

This is the answer

I hope this will be useful

Explanation:

Gandhiji choose to break the salt law because in his view, it was sinful to tax salt since it is such as essential item of our food that is used by the rich or the poor person in the same quantity.

Answer:

Gandhiji choose to break the salt law because in his view, it was sinful to tax salt since it is such as essential item of our food that is used by the rich or the poor person in the same quantity.

Answer:

here is your answer dear :)

Answer:

They all are 7 nice rivers of India

I know that u don't remember me

but I am jia

radhe radhe

Answer:

final answer is x⁴-1

Step-by-step explanation:

step1: (x-1)^8-4

step2: (x-1)^4

step3: x^4-1^4

step4: x⁴-1

Given to evaluate:

[tex] \tt = \dfrac{d}{dx} \bigg( \dfrac{ {x}^{8} - 1}{ {x}^{4} - 1} \bigg)[/tex]

Can be written as:

[tex] \tt = \dfrac{d}{dx}\dfrac{({x}^{4})^{2} - {(1)}^{2} }{ {x}^{4} - 1}[/tex]

[tex] \tt = \dfrac{d}{dx}\dfrac{({x}^{4} + 1)( {x}^{4} - 1)}{ {x}^{4} - 1}[/tex]

[tex] \tt = \dfrac{d}{dx}({x}^{4} + 1)[/tex]

We know that:

[tex] \tt \longrightarrow \dfrac{d}{dx}(f \pm g) = \dfrac{df}{dx} \pm \dfrac{dg}{dx} [/tex]

Using this result, we get:

[tex] \tt = \dfrac{d}{dx}({x}^{4})+ \dfrac{d}{dx}(1)[/tex]

We know that:

[tex] \tt \longrightarrow \dfrac{d}{dx}( {x}^{n} ) =n {x}^{n - 1} [/tex]

[tex] \tt \longrightarrow \dfrac{d}{dx}(k) =0[/tex]

Using this result, we get:

[tex] \tt = 4{x}^{3} + 0[/tex]

[tex] \tt = 4{x}^{3} [/tex]

Therefore:

[tex] \tt \longrightarrow\dfrac{d}{dx} \bigg( \dfrac{ {x}^{8} - 1}{ {x}^{4} - 1} \bigg) =4 {x}^{3} [/tex]

Which is our required answer.

[tex]\begin{gathered}\boxed{\begin{array}{c|c}\bf f(x)&\bf\dfrac{d}{dx}f(x)\\ \\ \frac{\qquad\qquad}{}&\frac{\qquad\qquad}{}\\ \sf k&\sf0\\ \\ \sf sin(x)&\sf cos(x)\\ \\ \sf cos(x)&\sf-sin(x)\\ \\ \sf tan(x)&\sf{sec}^{2}(x)\\ \\ \sf cot(x)&\sf-{cosec}^{2}(x)\\ \\ \sf sec(x)&\sf sec(x)tan(x)\\ \\ \sf cosec(x)&\sf-cosec(x)cot(x)\\ \\ \sf\sqrt{x}&\sf\dfrac{1}{2\sqrt{x}}\\ \\ \sf log(x)&\sf\dfrac{1}{x}\\ \\ \sf{e}^{x}&\sf{e}^{x}\end{array}}\\ \end{gathered}[/tex]