In angle a b c ,angle b=53 and angle a=73 if bisecor angle c meet is the opposite side ab is point d find he angle adc and bdc
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Subject:
Math -
Author:
norahclarke -
Created:
1 year ago
Answers 1
Answer:
ABC
∠A+∠B+∠C=180
50
+70+∠C=180
120
+∠C=180
∠C=180
−120
=60
Since CD is the bisector ∠C
So, ∠ACD=∠BCD=
2
∠C =
2 /60 =30
In triangle ADC
∠ACD+∠DAC+∠ADC=180
30 +50 +∠ADC=180
∠ADC=180 −80 ∠ADC=100
∠ADC+∠BDC=180
100 +∠BDC=180
∠BDC=180
−100
∠BDC=80
So in triangle ADC
∠DAC=50
,∠ACD=30
,∠ADC=100
In triangle BDC
∠DBC=70
,∠BCD=30
,∠BDC=80
And ∠BDC=80
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Author:
chefxg9a
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