Subject:
MathAuthor:
issacacostaCreated:
1 year agoAnswer:
[tex]used \: system \: for \: the \: liner \: equation \: the \: distance \: at \: the \: fisherman \: and \: the \: boobler \: meet \: in \: 8 \: miles.[/tex]
Step-by-step explanation:
[tex]speed \: in \: still \: water \: = 7 \: mph[/tex]
[tex]stream \: speed \: = 3 \: mph[/tex]
[tex]upstream \: speed \: of \: canoe \: 7 - 3 = 4 \: mph[/tex]
[tex]distance \: between \: fisherman \: and \: boobler \: is \: 14 \: miles[/tex]
[tex]let \: seperation \: distance = d[/tex]
[tex]meeting \: distance = 14 - d[/tex]
[tex] \frac{d}{4} = \frac{14 - d}{3} [/tex]
[tex]3d = 4(14 - d)[/tex]
[tex]3d = 56 - 4d[/tex]
[tex]3d + 4d = 56[/tex]
[tex]7d = 56[/tex]
[tex]d = 56[/tex]
[tex]hence.. \: distance \: is \: 8miles[/tex]
Author:
wizygbw
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