Given :-- A particle is thrown at an angle θ with speed v₀ with horizontal. After sometime particle moves with speed v at an angle β with horizontal. The correct relation between v₀ and v is?
Solution :-- Here, it is given that the particle is thrown at an angle v₀ at an angle θ and it moves with a speed v at angle β with horizontal after sometime
- As we know, during the whole journey of the projectile, the horzontal acceleration is zero so the horizontal velocity(vcosθ) is same.
- So we can equate the horizontal velocities at both the points.
⇒ v₀cosθ = vcosβ
→ So, that is the relation between v₀ and v
∴ The relation between v₀ and v is v₀cosθ = vcosβ
___________________________________________
Thank you, please mark as brainliest!
→Sathvik :)