temple at Ellora was built by Krishna III in the 9th century ​

Answer:

may

Explanation:

if we request our nieghbour he might give us a lift to the park

Answer:

might

Explanation:

okay pleasee see this

Answer:

Children don't know how to use the phone so if any app gets on and something or the other happens to the mobile

Explanation:

I advice them to not to take use the phones for much time

Answer:

Dialysis tubing is an artificial membrane, which is similar to the lining of the intestine.

A student investigated the diffusion of glucose through dialysis tubing by using the apparatus

Answer:

inside perimeter of the walkway = 75 14/15 m

Step-by-step explanation:

Given :  a park is 25 4/5 m long and 20 2/3 m wide . a walkway is to be constructed inside the park which is 2 3/8m wide,

To find : perimeter of park  

inside perimeter of the walkway

Solution:

Park length  25 4/5 m  = 25 + 4/5  m =  (125 + 4)/5 = 129/5 m

Park Width =  20 2/3 m = 20 + 2/3 m = (60 + 2)/3  = 62/3  m

Park perimeter = 2 ( Length + Width )

= 2 ( 129/5  + 62/3)

= 2( 387  + 310)/15

= 2(697)/15

= 1394 / 15

= 92  14/15  m

walkway is to be constructed inside the park which is 2 3/8m wide

2  + 3/8  m   = 19/8  Meter

8 times the width will be reduced  

8 * 19/8   = 19 m

inside perimeter of the walkway  = 92  14/15  - 19

= 75 14/15 m

Park perimeter =  92  14/15  m

inside perimeter of the walkway  = 75 14/15 m

Learn More:

What is the area of the jogging track which is 2 m wide that runs ...

brainly.in/question/11147790

perimeters of two similar triangles are 30cm and 40cm respectively ...

I hope the answer is clear to you any doubts or query feel free to ask

Answer:

inside perimeter of the walkway = 75 14/15 m

Step-by-step explanation:

Given :  a park is 25 4/5 m long and 20 2/3 m wide . a walkway is to be constructed inside the park which is 2 3/8m wide,

To find : perimeter of park  

inside perimeter of the walkway

Solution:

Park length  25 4/5 m  = 25 + 4/5  m =  (125 + 4)/5 = 129/5 m

Park Width =  20 2/3 m = 20 + 2/3 m = (60 + 2)/3  = 62/3  m

Park perimeter = 2 ( Length + Width )

= 2 ( 129/5  + 62/3)

= 2( 387  + 310)/15

= 2(697)/15

= 1394 / 15

= 92  14/15  m

walkway is to be constructed inside the park which is 2 3/8m wide

2  + 3/8  m   = 19/8  Meter

8 times the width will be reduced  

8 * 19/8   = 19 m

inside perimeter of the walkway  = 92  14/15  - 19

= 75 14/15 m

Park perimeter =  92  14/15  m

inside perimeter of the walkway  = 75 14/15 m