Answer:
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Explanation:
The pressure at the base of the mountain is 750mm of Hg and at its top is 600 mm of Hg. If the density of the air is 1kg/m^3, then what is the height of the mountain?
The difference in pressures is 150 mm of Hg or 0.15 m of Hg. This is equivalent to a pressure of 0.15*13600*9.8 Pa where 13600 kg/m^3 is the density of mercury. This is equal to 1*h*981 where ‘h’ is the height of the mountain and 1 kg/m^3 is the density of air. From these, the height of the mountain is 0.15*13600 or 2040 m.