Answer:
In the given figure, ∠X = 62° and ∠XYZ = 54° ∠XYZ + ∠XZY + ∠YXZ = 180° …(i) [Angle sum property of a triangle] ⇒ 54° + ∠XZY + 62° = 180° ⇒ ∠XZY + 116° = 180° ⇒ ∠XZY = 180° – 116° = 64° Now, ∠OZY = 1/ 2 × ∠XZY [∵ZO is bisector of ∠XZY] = 1 /2 × 64° = 32° Similarly, ∠OYZ = 1/2 × 54° = 27° Now, in ∆OYZ, we have ∠OYZ + ∠OZY + ∠YOZ = 180° Angle sum property of a triangle] ⇒ 27° + 32° + ∠YOZ = 180° ⇒ ∠YOZ = 180° – 59° = 121° Hence, ∠OZY = 32° and ∠YOZ = 121°
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solomonbarajas
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