48. भगवान कोयादरखने का सर्वश्रेष्ठ माध्यमक्या है? (गीता8.5) क. शांतिपूर्वक ध्यान द्वा ग. अपना काम करनेसे​

Answer:

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Answer:

The correct answer will be -

लेन्सची शक्ती +4.0 D असेल. The power of the lens will be +4.0 D.

Explanation:

Given in the question -

• बहिर्वक्र भिंगाची फोकल लांबी 25 सेमी आहे.

आता आपल्याला लेन्सची शक्ती शोधावी लागेल.

आपल्याला माहित आहे की लेन्सची शक्ती ही लेन्सच्या फोकल लांबीची परस्पर आहे.We know that power of the lens is the reciprocal of the focal length of the lens.

So, power of the lens =  [tex]\frac{1}{focal\ length(in \ m)}[/tex]

Focal length = +25 cm = +0.25 m

Power of the lens = [tex]\frac{1}{0.25} = + 4.0\ D[/tex]

So,लेन्सची शक्ती +4.0 D असेल (the power of the lens will be +4.0 D).

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Answer:

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Answer:

Identity I: (a + b)2 = a2 + 2ab + b2

Identity II: (a – b)2 = a2 – 2ab + b2

Identity III: a2 – b2= (a + b)(a – b)

Identity IV: (x + a)(x + b) = x2 + (a + b) x + ab

Identity V: (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca

Identity VI: (a + b)3 = a3 + b3 + 3ab (a + b)

Identity VII: (a – b)3 = a3 – b3 – 3ab (a – b)

Identity VIII: a3 + b3 + c3 – 3abc = (a + b + c)(a2 + b2 + c2 – ab – bc – ca)

Step-by-step explanation:

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[tex]\large\mathfrak\pink{♡answer♡}[/tex]

• Identity I: (a + b)² = a² + 2ab + b²
• Identity II: (a – b)² = a² – 2ab + b²
• Identity III: a² – b² = (a + b)(a – b)
• Identity IV: (x + a)(x + b) = x² + (a + b) x +ab
• Identity V: (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca
• Identity VI: (a + b)3 = a³ + b³ + 3ab (a + b)
• Identity VII: (a – b)³ = a³ – b³ – 3ab (a – b)
• Identity VIII: a³ + b³ + c³ – 3abc = (a + b + c)(a² + b² + c² – ab – bc – ca)

Answer:

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Explanation:

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