TISCO was started in which year and who started it.​

Answer:

Engage: Interacting with external stakeholders to provide a good understanding of needs, to promote transparency, and to foster good relationships with all stakeholders. Plan: Creating a shared understanding of the vision, status and improvement directions for all four dimensions and all products and services.

Answer:

Wow!!what a pleasant morning. I and my family are sitting along the river,enjoying the lovingly morning. My dog Fudge,my two little sister,my parents and I are having fun by eating and drinking juices .There are many flowers. we are sitting under the shade of the tree.the sun has arrised and bright sunny day today!.

Answer:

Just write about a landscape for it.

Answer:

last/only

mark me brainlist

Step-by-step explanation:

If a rectangular sheet is rolled along its breadth than the dimensions will be 22cm as height and 11cm as circumference of the circle of the cylinder.

Circumference of circle= 2πr

11cm                                = 2*22/7*radius

radius                              = 7/4cm

So, height is 22cm and radius is 7/4cm.

Curved surface area of a cylinder= 2πrh

                                                       = 2*22/7*7/4*22

                                                        = 242[tex]cm^{2}[/tex]

Given,

Dimensions of a rectangular sheet = 22 cm × 11 cm.

It is rolled along the shorter side to form a cylinder.

To find,

The curved surface area of the cylinder formed.

Solution,

This problem can be simply solved by following the below process.

It can be seen that when a rectangular sheet is rolled to form a cylinder, a hollow cylinder will be obtained and the curved surface area of this cylinder will be equal to that of the original rectangular sheet.

So, mathematically,

The curved surface area of the cylinder = the area of the rectangle

⇒ [tex](CSA)_{cyl}=A_{rect}[/tex]

Here, [tex]A_{rect}[/tex] can be determined as,

[tex]A_{rect}=22\times 11[/tex] cm²

⇒ [tex]A_{rect}=242[/tex] cm²

Since both areas will be the same. So,

[tex](CSA)_{cyl}=242 \hspace{3} cm^{2}[/tex].

Therefore, the curved surface area of the cylinder formed will be 242 cm².