Comparison of karnataka and Uttarakhand dresses

Answer:

covert 89(10) to binary and to octal

Given,

A decimal number 89₁₀.

To Find,

The binary and octal form of this number.

Solution,

To convert Decimal to binary and octal follow the given steps.

• The conversion of decimal to binary is done in a variety of ways. One of the ways to convert a decimal to a binary is to divide the decimal number by 2 times. Then, the rest is marked down until we get 0 as the final quotient. After this step, the remainder is written in order to get the binary value of the given decimal number.

• The conversion of decimal to octal occurs when we need to find an equal to any number. In this case, we need to convert the decimal number into its equal octal number. In the numerical system, each type has its own base number i.e. the octal number has a base number of 8 and the decimal number has a base number of 10. To convert a decimal into octal, we need to divide the decimal number by octal. base number 8 and write the remainder obtained by subtraction to get the same octal number.

Hence, the binary form of 89₁₀ is 1011001₂ and the octal form is 131₈.

In situations with high risks, credit might create further problems for the borrower. This is also known as a debt-trap. Taking credit involves an interest rate on the loan and if this is not paid back, then the borrower is forced to give up his collateral or asset used as the guarantee, to the lender.

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Answer:

In situations with high risks credit might create further problems for the borrower. This is also known as a debt-trap. Taking credit involves an interest rate on the loan and if this is not paid back then the borrower is forced to give up his collateral or asset used as the guarantee to the lender.

Answer:

Yet only one set of equations is considered so mathematically challenging that it's been chosen as one of seven “Millennium Prize Problems” endowed by the Clay Mathematics Institute with a $1 million reward: the Navier-Stokes equations, which describe how fluids flow

Step-by-step explanation:

(i) Let x represent the number of Rs 10 fare

increases. Then 70 10 + x is the price per

passenger and 300 20 - x is the number of

passengers.

The income is the number of passengers

multiplied by the price per ticket. Let I x( )

represent income as a function of x .

Now I x( ) = ( ) 300 20 70 10 − + x x ( )

= 20 15 10 7 ( ) − + x x ( )( )

200 105 8 ( ) x x = + − 2

200 8 105 ( ) x x =− −2 −

200( ) x x8 16 16 105 =− −2 +−−

200( ) x x8 16 121 =− −2 + −

200( ) x x8 16 24200 =− −2 + +

200 4 24200 ( ) x =− − 2 +

(ii) From above equation it is clear that I x( ) is

maximum at x = 4 and this maximum value

is 24200. This means the company should

make 4 fare increases of Rs 10 to maximize