Two forces of magnitude F1= 10N and F2 =20N act on a body in a direction making angle a = 30 and b = 60 degrees respectively with the x-axis. Thus the resultant force Fr acting on the body is given by,
Fr = i (F1 cos a + F2 cos b) + j ( F1 sin a + F2 sin b)
= i ( 10 cos 30 + 20 cos 60) + j ( 10 sin 30 + 20 sin 60).
= i { 10 x (√3/2) + (20 /2)} + j { (10/2)+ 20 x(√3/2)}
A man has a 73% chance of making a basket on a free-throw. Making or missing shots do not affect the chance of future shots. What is the probability that he will make between 3 and 5 baskets (inclusive) out of 10, and why?A man has a 73% chance of making a basket on a free-throw. Making or missing shots do not affect the chance of future shots. What is the probability that he will make between 3 and 5 baskets (inclusive) out of 10, and why?A man has 73% chance of making a basket on a free throw, so, a man also have 27% of failing to make itA man has a 73% chance of making a basket on a free-throw. Making or missing shots do not affect the chance of future shots. What is the probability that he will make between 3 and 5 baskets (inclusive) out of 10, and why?A man has 73% chance of making a basket on a free throw, so, a man also have 27% of failing to make itSo, the probability if:A man has a 73% chance of making a basket on a free-throw. Making or missing shots do not affect the chance of future shots. What is the probability that he will make between 3 and 5 baskets (inclusive) out of 10, and why?A man has 73% chance of making a basket on a free throw, so, a man also have 27% of failing to make itSo, the probability if:He makes three baskets out of ten:A man has a 73% chance of making a basket on a free-throw. Making or missing shots do not affect the chance of future shots. What is the probability that he will make between 3 and 5 baskets (inclusive) out of 10, and why?A man has 73% chance of making a basket on a free throw, so, a man also have 27% of failing to make itSo, the probability if:He makes three baskets out of ten:(0.73)^3 *(0.27)^7A man has a 73% chance of making a basket on a free-throw. Making or missing shots do not affect the chance of future shots. What is the probability that he will make between 3 and 5 baskets (inclusive) out of 10, and why?A man has 73% chance of making a basket on a free throw, so, a man also have 27% of failing to make itSo, the probability if:He makes three baskets out of ten:(0.73)^3 *(0.27)^7He makes four out of ten:A man has a 73% chance of making a basket on a free-throw. Making or missing shots do not affect the chance of future shots. What is the probability that he will make between 3 and 5 baskets (inclusive) out of 10, and why?A man has 73% chance of making a basket on a free throw, so, a man also have 27% of failing to make itSo, the probability if:He makes three baskets out of ten:(0.73)^3 *(0.27)^7He makes four out of ten:(0.73)^4 *(0.27)^6A man has a 73% chance of making a basket on a free-throw. Making or missing shots do not affect the chance of future shots. What is the probability that he will make between 3 and 5 baskets (inclusive) out of 10, and why?A man has 73% chance of making a basket on a free throw, so, a man also have 27% of failing to make itSo, the probability if:He makes three baskets out of ten:(0.73)^3 *(0.27)^7He makes four out of ten:(0.73)^4 *(0.27)^6He makes five out of ten:A man has a 73% chance of making a basket on a free-throw. Making or missing shots do not affect the chance of future shots. What is the probability that he will make between 3 and 5 baskets (inclusive) out of 10, and why?A man has 73% chance of making a basket on a free throw, so, a man also have 27% of failing to make itSo, the probability if:He makes three baskets out of ten:(0.73)^3 *(0.27)^7He makes four out of ten:(0.73)^4 *(0.27)^6He makes five out of ten:(0.73)^5 *(0.27)^5A man has a 73% chance of making a basket on a free-throw. Making or missing shots do not affect the chance of future shots. What is the probability that he will make between 3 and 5 baskets (inclusive) out of 10, and why?A man has 73% chance of making a basket on a free throw, so, a man also have 27% of failing to make itSo, the probability if:He makes three baskets out of ten:(0.73)^3 *(0.27)^7He makes four out of ten:(0.73)^4 *(0.27)^6He makes five out of ten:(0.73)^5 *(0.27)^5Calculate them and sum their result, that’s the answer