⌬ According to the Question :
Given That-
[tex] \\ \longrightarrow\sf \: Ka = {a}^{2}c[/tex]
[tex] \\ [/tex]
★Need To Find-
- Calculate Dissociation Constant Of Acid
[tex] \\ [/tex]
★Formula To Be Used-
[tex] \small\longrightarrow \sf \: \boxed{\bf\pink{a = \frac{Percent \: Dissociation}{100} }}[/tex]
[tex] \\ [/tex]
❒ Let's Find-
[tex] = \sf \: \frac{0.5}{100} \\ [/tex]
[tex] \sf➪ \: 5 × 10⁻⁴ \\ [/tex]
[tex] \sf➪ \: C = 0.02 M \\ [/tex]
[tex] \sf➪ \: 2 × 10⁻²M \\ [/tex]
[tex] \\ {\underline{\rule{160pt}{4pt}}} [/tex]
✠Hence, Kₐ
[tex] \\ [/tex]
[tex]\longmapsto \sf \: (5 \times 10⁻⁴) ^{2} \times 2 \times 10 ^{ - 2} \\ \\ \longmapsto \sf \: 25 \times 10⁻⁸ \times 2 \times {10}^{ - 2} \: \: \: \\ \\ \longmapsto \sf \: 50 \times 10 ^{ - 10} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \longmapsto \sf \: \boxed{\bf\pink{ 5 \times {10}^{ - 9} }} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]
❛❛ Therefore, The Dissociation Constant Of Acid Is = 5 × 10⁻⁹ ❜❜
[tex] \\ {\underline{\rule{300pt}{9pt}}} [/tex]