निम्नलिखित में स्त्रीलिंग शब्द है (A) पक्षी (B) बटेर (C) नेत्र (D) गन्ना​

Answer:

Frequency density

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Answer:

class frequency divided by the width of the class is known as​ class width

Step-by-step explanation:

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Answer:

This rotting dead matter in the soil is called humus. Below the layer of humus, there is a clear water level which contains dissolved part from the soil. Below water layer, there are layers of clay, sand, gravel and stones.

Explanation:

Answer:

Gravel is a kind of tiny stones.The amount of gravel present in a good top-soil is very small. In a good top-soil, gravel is present in very small amount.The main rock particles present in the top-soil are sand, clay and silt. So, depending on its composition, a soil can be classified as sandy soil, clayey soil or loamy soil.

Explanation:

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This theorem states that, In a right angled triangle, the square of the hypotenuse is equal to the sum of square of the other two sides.

Normally, to solve for right angled triangles, we use Pythagoras theorem.

As we went through the concept about Pythagoras theorem, Now Let's, move on finding the solution for our question.

We have been given that, Two perpendicular sides of a right angled triangle are 12 cm and 35 cm respectively. And We have been asked to find the hypotenuse.

(Refer the attachment for the figure)

Given,

• AB = 12 cm
• BC = 35 cm

We know that,

[tex]{\boxed{\bullet\:{AB^2\:+\:BC^2\:=\:AC^2}}}[/tex]

Substituting values in Formula, we get,

[tex]\sf\implies{AB^2\:+\:BC^2\:=\:AC^2}[/tex]

[tex]\sf\implies{(12)^2\:+\:(35)^2\:=\:AC^2}[/tex]

[tex]\sf\implies{144\:+\:1225\:=\:AC^2}[/tex]

[tex]\sf\implies{1369\:=\:AC^2}[/tex]

[tex]\sf\implies{AC\:=\:{\sqrt{1369}}}[/tex]

[tex]\sf\implies{AC\:=\:37\:cm}[/tex]

Hence, the hypotenuse in the right angled triangle ABC is 37 cm.

Answer:

The hypotenuse is 37 cm

Step-by-step explanation:

To solve this question we will be needing the pythagoras theorem which is [tex]h^{2}=p^{2}+b^{2}[/tex] where h is hypotenuse p is perpendicular and b is base

Now we are given 2 perpendicular lines which means both of them are perpendicular and base by putting it in the formula we will get

[tex]h^{2} = 12^{2} +35^{2} \\h^{2} =144+1225\\h^{2} = 1369\\h=\sqrt{1369} \\h= 37[/tex]

Answer:

To,

The Principal/Headmaster,

[School Name],

[School Address],

[Date].

Subject: Name change request letter.

Dear Sir/Madam,

With due respect, I am writing this letter to inform you that I am ________ [Write your name], son/daughter of ____________ [Write your father name]. I am a student of class ______ [Mention your class] in your school.

As per record of school, my name is “________” [Write your wrong name] which is incorrect. My correct name is“________” [Write your correct name]. That’s why I’m requesting you to update your school records with the correct name instead of my wrong name.

If you can announce the correct name for school students through a notice I will be thankful to you.

Thanking you in anticipation.

Best Regards,

[Name],

[Class & Section],

[Your Address],

[Contact Details].

Application For Name Change In School

To,

The Principal,

[Name of the School],

[School Location],

[Date].

Subject: Name change application in school.

Dear Sir/Madam,

I am writing to you because I would like to request that you correct my name on all the officials of the school.

My name is spelled ________” [Mention your correct name] and on my all school documents, it is spelled like this “_________” [Mention your wrong name]. (You can mention your actual problem and situation).

Therefore, I formally request you to please change/update the name in order to prevent any issues in the future. In case, if you require any other clarification or documents, I can be contacted at _______ [Mention your mobile number] or by email __________ [Mention your email address].

Thank you in advance.

Yours Faithfully,

[Your Name],

[Class & Section],

[Roll No].