Newton ne Kya khoj ki thi ? akhbari lota

Answer: False

End product of protein is Amino acids during glucogenedis amino acid converted to Glucose .

Explanation:

Answer:

Glucose is end product of protein metabolism.

Answer:

I'm looking forward to see you

Explanation:

I am looking forward to see you

सुढर या उत्तम विचार बेहतर ख़याल

Answer:

Zeroes are 10 and -8.

Step-by-step explanation:

Given,

x² - 2x - 80 = 0

x² - 10x + 8x - 80 = 0

x(x - 10) + 8(x - 10) = 0

(x - 10)(x + 8) = 0

x - 10 = 0 and x + 8 = 0

x = 10 and x = -8.

Therefore x = 10, -8

Let these zeroes be m and n.

Sum of zeroes = m + n = -b/a

Here a and b are coefficient of x² and x respectively.

Sum of zeroes = 10 - 8 = -(-2)/1

Sum of zeroes = 2 = 2

Hence verified.

Product of zeroes = m*n = c/a

Here c is constant term of equation.

Product of zeroes = 10*(-8) = -80/1

Product of zeroes = -80 = -80

Hence verified.

 Given,

The polynomial x²-2x-80

To find,

The zero of the given polynomial x²-2x-80 and verify the relationship between zeroes and the coefficients.

Solution,

We can simply solve for the zero of the polynomial x²-2x-80 by putting the polynomial equals to 0.

                 x²-2x-80 =0

Now factorize the given polynomial

                  x²-(10-8)x-80=0

Using Distributive property

                   x²-10x+8x-80=0

Taking x common from the first 2 terms and 8 from the last two terms

                  x(x-10)+8(x-10)=0

Taking (x-10) common from both sides

                  (x-10)(x+8)=0

This implies either the first part is zero or the second part is zero.

                (x-10)=0                  (x+8)=0

                  x=10                        x=-8

So the zeroes of the polynomial x²-2x-80 are 10 and -8.

Sum of zeroes = -b/a  where 'b' is the coefficient of x and 'a' is the coefficient of x².

                         =  -(- 2)/1  

                         =   2

Product of zeros = c/a  where 'c' is the constant term and 'a' is the coefficient of x².

                            =80/1

                            =80  

As we can see that the sum of 10 and -8 is 2 and their product is 80 which is verified by the relationship between zeroes and the coefficients.

Hence, the required zeroes of polynomial x²-2x-80 are 10 and -8 and the relationship between zeroes and coefficients is verified.