Answer:
Centroid of a triangle with vertices (x1,y1);(x2,y2) and (x3,y3) is calculated by the formula
(3x1+x2+x3,3y1+y2+y3)
Let the third vertex of the triangle be (x,y)
So, centroid =(33−1+x,37+5+y)=(1,3)
⇒(32+x,312+y)=(1,3)
⇒2+x=3;12+y=9
⇒x=1;y=−3
Hence the third vertex of the triangle is (1,−3)
Step-by-step explanation:
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