Explain the features of topography which are common in all highlands(Pakistan)

Answers 1

Answer:

The one feature common among all of them is that they are dangerous and rocky and thus make traveling through them difficult. Most of these highlandshave acted as barriers to prevent any kind of movement through them

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Other related questions that may help you

Its known that gases have the maximum intermolecular spaces. But is a maximum amount they can expand to in a container? or if i take a very large container with some gas it will just expand and increase its volume filling the whole container?so is the expansion of gas definite to an extent or indefinite? and if its definite , whats its maximum point?​

Answer:

Using ideal gas equation

Explanation:

from equation of state, we know the

PV=nRT

for 1mole

PV=RT

or P=

V

RT

This is the critical point.

How to write Hindi in english

Answer:

Hindi is written in hindi

Answer:

by translation and or one app named duolingo also will help you to learn various languages

Find K In The Give Figure (with explanation) ​
question img

Answer:

k is 165 degrees

Step-by-step explanation:

k+150+30=180

k+180=180

k+180-15=180

k+165=180

Then k is 165

Answer:

Sum of all exeter and interior angle is 360

Step-by-step explanation:

Now K-15+30+90+K+150=360

2K+255=360

2K=360-255

2K=105

K=105/2

K=52.5

tan a + b = √3 tan , a - b is = 1 and A,B (b is lesser than a ) are acute angles , find the value of A and B . please help step by step .​

Answer:

the value of A and B that satisfy the given equation is 45° and 15°, respectively

Step-by-step explanation:

Given,

tan(A + B) = √3

Since, A + B ≤ 90°,

Therefore,

A ≤ 90° and B ≤ 90°

According to the table, the angle at which tan acquires the value √3, is at 60°.

Therefore,

tan(A + B) = √3 = tan 60°

tan(A + B) = tan 60°

A + B = 60° ⇢ (i)

tan(A – B) = 1/√3

According to the table, the angle at which tan acquires the value 1/√3, is at 30°. Therefore,

tan(A – B) = 1/√3 = tan 30°

tan(A – B) = tan 30°

A – B = 30° ⇢ (ii)

Adding equation (i) and (ii),

2A = 90°

A = 45°

Putting the value of A in equation (i),

45° + B = 60°

B = 60°- 45°

B = 15°

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