Answer:
Let x
1
=a∴x
2
=ar,x
3
=ar
2
and
y
1
=b ∴y
2
=br,y
3
=br
2
Now A(a,b),B(ar,br),C(ar
2
,br
2
)
Now slope of AB=
a(1−r)
b(1−r)
=
a
b
and
slope of BC=
ar(1−r)
br(1−r)
=
a
b
as slope of AB= slope of BC
∴AB∥BC but point B is common so
A,B,C are collinear.
Author:
rockette
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