Name ten cottage industries of Pakistan.​

Answer:

eena mina dicka

Explanation:

same to casita

Answer:

Choose the correct answer. 1. The narrator describes the age of two as a tender age because at this age, his faculties were not fully developed. b. at this time, he led a very comfortable life. C. he was naïve and had no idea about the world outside. 2. The extraordinary spectacle that the narrator watched was the blue roof slates baked by the sun. b. four cats romping around with every indication of joy. the open kitchen window with a small roof above it. C. and res tit e ro each dr in the context in which they are used in the

Answer:

Support for Socialism: Socialists formed an organization called 'Second International' to spread socialist ideas. Workers in Germany and England began forming associations to fight for better living conditions. They set up funds for members in distress, reduction of working hours, and the right to vote

Answer:

Q20)A sum of ₹ 500 is in the form of notes of denominations of ₹ 5 and₹ 10. If the total number of notes is 90, find the number of notes of each type. The number of ₹ 10 notes = 90-x = 90-80 = 10 .

Step-by-step explanation:

Q20)A sum of ₹ 500 is in the form of notes of denominations of ₹ 5 and₹ 10. If the total number of notes is 90, find the number of notes of each type. The number of ₹ 10 notes = 90-x = 90-80 = 10 .

Given:

Total sum = 500

Total number of notes used = 90

To find:

Total number 5 and 10 rupees notes used

Solution:

Let,

total number of 5 rupee notes be [tex]x[/tex]

and total number of 10 rupee notes be [tex]y[/tex]

if we multiply the number of notes into the denominator we should get the total of 500. Hence,

[tex]5x + 10y= 500[/tex]

Let this be equation 1.

Since we know total number of notes are 90. Therefore,

[tex]x+y=90[/tex]

multiply both sides by 5 to have an equal value of [tex]x[/tex] as in equation 1. We get,

[tex]5x+5y=450[/tex]

Let this be equation 2.

Now, subtract equation 2 from equation 1 and solve for y.[tex]5x+10y-(5x+5y)=500-450\\5x+10y-5x-5y=50\\5y=50\\y=50/5\\y=10[/tex]

Insert the value of y in equation 1 and solve for x.

[tex]5x+10(10)= 500\\5x+100=500\\5x=500-100\\5x=400\\x=400/5\\x=80[/tex]

Therefore,

total number of 5 rupee notes = 80

and total number of 10 rupee notes = 10

Answer:

Solution:

L.C.M. of 4, 9 and 10 is 180.

Prime factors of 180 = 2 x 2 x 3 x 3 x 5

Here, prime factor 5 has no pair. Therefore 180 must be multiplied by 5 to make it a perfect square.

\therefore180\times5=900∴180×5=900

Hence, the smallest square number which is divisible by 4, 9 and 10 is 900.

Answer:

The smallest perfect square number which is exactly divisible by each of the 4, 6, 10 and 12 is 900 and [tex]\sqrt{900} [/tex] = 30

Step-by-step explanation:

We have to find the smallest perfect square number which is exactly divisible by each of the 4, 6, 10 and 12.

To find the smallest perfect square number which is exactly divisible by each of the 4, 6, 10 and 12, we have to first find the smallest number which is divisible by 4, 6, 10 and 12.

So, Smallest number divisible by 4, 6, 10 and 12 = LCM(4, 6, 10, 12).

[tex]\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \:\: \begin{array}{c|c} {\underline{\sf{2}}}&{\underline{\sf{\:\:4 \: , \: 6\:, \: 10\:,\:12 \: \: }}}\\{\underline{\sf{2}}}&{\underline{\sf{\:\:2 \: , \: 3\:, \: 5\:,\:6 \: \: }}}\\ {\underline{\sf{3}}}&{\underline{\sf{\:\:1 \: , \: 3\:, \: 5\:,\:3 \: \: }}}\\{\underline{\sf{}}}&{\sf{\:1, \: \:1\:, \: 5 \:,\:1 \: }} \end{array}\end{gathered}\end{gathered}\end{gathered} \\ \\ \end{gathered} [/tex]

So,

[tex]\sf \:LCM(4, 6, 10, 12) = 2 \times 2 \times 3 \times 5 \\ \\ [/tex]

[tex]\sf\implies \sf \:LCM(4, 6, 10, 12) = 60 \\ \\ [/tex]

So, 60 is the smallest square number which is exactly divisible by each of the 4, 6, 10 and 12.

[tex]\sf \:Prime \: factorization \: of \: 60 = 2 \times 2 \times 3 \times 5 \\ \\[/tex]

We concluded from above factorization that prime factors 3 and 5 are not in pairs.

So, in order to get a perfect square, each factor of 60 must be in pairs.

[tex]\sf\implies 60 \: must \: be \: multiplied \: by \: 3\times 5 , \: i.e \: by \: 15 \\ \\[/tex]

[tex]\sf\implies Required\:number = 60 × 15 = 900 \\ \\[/tex]

Hence,

The smallest perfect square number which is exactly divisible by each of the 4, 6, 10 and 12 is 900

and

[tex]\sf \: \sqrt{900} = \sqrt{2.2.3.3.5.5} = 2.3.5 = 30 \\ \\ [/tex]

[tex]\rule{190pt}{2pt}[/tex]

Additional Information

[tex]\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{\pmb{{More \: identities}}}} \\ \\ \bigstar \: \bf{ {(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} }\:\\ \\ \bigstar \: \bf{ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} }\:\\ \\ \bigstar \: \bf{ {x}^{2} - {y}^{2} = (x + y)(x - y)}\:\\ \\ \bigstar \: \bf{ {(x + y)}^{2} - {(x - y)}^{2} = 4xy}\:\\ \\ \bigstar \: \bf{ {(x + y)}^{2} + {(x - y)}^{2} = 2( {x}^{2} + {y}^{2})}\:\\ \\ \bigstar \: \bf{ {(x + y)}^{3} = {x}^{3} + {y}^{3} + 3xy(x + y)}\:\\ \\ \bigstar \: \bf{ {(x - y)}^{3} = {x}^{3} - {y}^{3} - 3xy(x - y) }\:\\ \\ \bigstar \: \bf{ {x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} )}\: \end{array} }}\end{gathered}\end{gathered}\end{gathered}[/tex]