A bullet having mass of 10gm moving with a speed of 1.5m/s penetrates a thick wooden plank of mass 90g. the plank was initially embedded and both moved together. determine their velocity
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Subject:
Geography -
Author:
patcheshouse -
Created:
1 year ago
Answers 1
Explanation:
the mass of bullet m1=10 g=0.01 kg,initial speed of bullet u1=1.5 ms−1,mass of wooden plank m2=90 g=0.09 kg,final velocity of plank + bullet = v andinitial speed of wooden plank u2=0Here, we apply the law of conservation of momentum, i.e., Final momentum = Initial momentum.m1u1+m2u2=m1v+m2v0.01×1.5+0.09×0=0.01×v+0.09×v0.015=0.1v
On solving
v
=
0.15
m
s
−
1
.
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Author:
fatty
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Rate an answer:
9
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