panjabchya maidani pradeshat pramukhane sheti vyavsay chalto​

Answer:

Astha borrowed approx. [tex]\text{Rs}30021[/tex].

Step-by-step explanation:

Let the sum Astha borrowed be [tex]$x$[/tex].

Then, using [tex]S.I=\frac{p*r*t}{100}[/tex], where [tex]p,r,t[/tex] are principle, rate  & time respectively.

[tex]$$\begin{aligned}&\left(\frac{x \times 7 \times 2}{100}\right)+\left(\frac{x \times 6 \times 4}{100}\right)+\left(\frac{x \times 9 \times 1}{100}\right)=14110 \\&\left(\frac{14 x}{100}+\frac{24 x}{100}+\frac{9 x}{100}\right)=14110 \\\frac{47 x}{100}=14110 \\& x=\frac{14110\times 100}{47}=30021 .27\end{aligned}$$[/tex]

Hence, sum borrowed[tex]$=$ Rs 30021.27[/tex] or approximately Rs. [tex]30021[/tex].

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Answer:

Total amount of money Astha borrowed= Rs 17000

Step-by-step explanation:

In the above question:

Given:

1. R(rate)= 7%

   T(time)= 2 years

2. R(rate)= 6%

    T(time)= 4 years

3.    R(rate)= 9%

    T(time)= 5 years

To find:

Total amount borrowed?

Solution:

Total interest= Rs 14110

We know, the formula for Simple interest as:

S.I= P×R×T/100

P= principle amount(here borrowed amount)

R= Rate of interest

T= Time

Let the total amount borrowed be 'x'

Then, total amount borrowed at the end of 11years will be;

S.I= P1×R1×T1/100+P2×R2×T2/100+P3×R3×T3/100

14110= x×7×2/100+x×6×4/100+x×9×5/100

14110= 14x/100+24x/100+45x/100(common denominator)(x is also common)

14110= 14x+24x+45x/100          

14110= 83x/100

  83x= 14110×100

      x= 1411000/83

      x= 17000

The amount of money she borrowed was Rs17000

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Answer:

The Equator is the line of 0 degrees latitude. Each parallel measures one degree north or south of the Equator, with 90 degrees north of the Equator and 90 degrees south of the Equator. The latitude of the North Pole is 90 degrees N, and the latitude of the South Pole is 90 de

Explanation:

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Answer:

0°

Explanation:

The value of equator is 0° and the latitude of the poles are 90°N and 90°S (Fig.

Answer:

Title bar in MS - Excel displays name of the worksheet

THE LENGTH OF THE TRAIN IS 325m

Given,

Speed of the train = 130 km/hr

Time taken by the train to cross the pole = 9 seconds.

To Find,

The length of the train.

Solution,

First, we will convert the speed of the train in m/sec

So,

130 km/hr = 130*5/18 = 650/18 m/sec

Now,

Length of pole = Speed of train*time taken by the train to cross the pole.

Length of the pole = 650/18*9 = 325 m

Hence, the length of the train is 325 m.