Answer:
value of x = (p+q)/3 or (p-q)/3
Step-by-step explanation:
given that :
9x² - 6px + (p² - q²) = 0
the above equation can be solved using
x =x= [ -(-6p)−(−6p) ± \sqrt{(-6p)^2 - 4(9)(p^2-q^2)}
(−6p)
2
−4(9)(p
2
−q
2
)
] ÷ 2(9) ⇒ eq1
this is the most fundamental formula for solving x which is as
x = -bx=−b ± \sqrt{b^2-4ac}
b
2
−4ac
÷ (2a)
where a = 9 ; b = (-6p) ; c = (p^2-q^2)a=9;b=(−6p);c=(p
2
−q
2
) from the general equation
ax^2 + bx + c =0ax
2
+bx+c=0
from eq 1 ;
x = [ 6p ± \sqrt{36p^2-36p^2+36q^2}
36p
2
−36p
2
+36q
2
] ÷ (18)
x = [ 6p ± 6q ] ÷ 18
x = [p ± q ] ÷ 3
x = (p+q)/3 or (p-q)/3