Answer:
625m
Explanation:
The initial velocity travelled is 625m
The accleration is a = 10m/s2
The time is t=5s
Apply the equation of motion.
yu+at
The velocity is v=0+10.5=50m/s.
The distance travelled in the first 5s is
0.5+10.52 125 m
The dis tan ce travelled in the following 10s is
s1=uti=50.10=500 m
The total distance travelled is
d=s+si = 125+500=625 m