how much time does a half boiled egg take to digest​

Answer:

Answer:

1. Chief minister

2. Governor

3. Members of Legislative Council

4. Members of Legislative Assembly

5. State Legislative Assembly

6. Legislative Council

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Step-by-step explanation:

∵ Mode = 38.

∴ The modal class is 30-40.

Mode =  l + f 1 − f 0 2 f 1 − f 0 − f 2 × h l+f1−f02f1−f0−f2×h

= 30 + 16 − 12 32 − 12 − x 16−1232−12−x x 10

= 38 4 20 − x 420−x x 10 = 8 8 (20 - x)

= 40 20 -

x = 5

X = 15

[tex]\large\underline{\sf{Solution-}}[/tex]

The frequency distribution table is

[tex]\begin{gathered} \begin{array}{|c|c|} \bf{Class \: Interval} & \bf{Frequency} \\ \\ 0 - 10 & 7   \\ \\10 - 20 & 9  \\ \\20 - 30 & 12  \\ \\30 - 40 & 16  \\ \\40 - 50 & x \\ \\50 - 60 & 6 \\ \\60 - 70 & 11 \end{array}\end{gathered} \\ [/tex]

Given that,

[tex]\rm \: Mode = 38 \\ [/tex]

[tex]\bf\implies \:Modal \: class \: = \: 30 - 40 \\ [/tex]

[tex]\rm \: f_0 = 12 \\ [/tex]

[tex]\rm \: f_1 = 16 \\ [/tex]

[tex]\rm \: f_2 = x \\ [/tex]

[tex]\rm \: h \: = \: 10 \\ [/tex]

[tex]\rm \: l \: = \: 30 \\ \\ [/tex]

We know, Mode for a continuous series is given by

[tex] \red{\boxed{ \boxed{\sf{Mode \: = \: l \: + \: \bigg(\dfrac{f_1 \: - \: f_0}{2f_1 \: - \: f_0 \: - \: f_2} \bigg) \: \times \: h }}}} \\ [/tex]

where,

l is lower limit of modal class.

[tex] \sf{f_1} [/tex] is frequency of modal class

[tex] \sf{f_0} [/tex] is frequency of class preceding modal class

[tex] \sf{f_2} [/tex] is frequency of class succeeding modal class

h is class height.

So, on substituting the values in above formula, we get

[tex]\rm \: \: 38= 30 + \bigg[\dfrac{16 - 12}{2 \times 16 - 12 - x} \bigg] \times 10\\[/tex]

[tex]\rm \: \: 38 - 30 = \bigg[\dfrac{4}{32 - 12 - x} \bigg] \times 10\\[/tex]

[tex]\rm \: \: 8 = \bigg[\dfrac{4}{20 - x} \bigg] \times 10\\[/tex]

[tex]\rm \: \: 2 = \bigg[\dfrac{1}{20 - x} \bigg] \times 10\\[/tex]

[tex]\rm \: \: 1 = \bigg[\dfrac{1}{20 - x} \bigg] \times 5\\[/tex]

[tex]\rm \: 20 - x = 5 \\ [/tex]

[tex]\rm \: - x = 5 - 20\\ [/tex]

[tex]\rm \: - x = - 15 \\ [/tex]

[tex]\bf\implies \:x = 15 \\ \\ [/tex]

[tex]\rule{190pt}{2pt} \\ [/tex]

Additional Information :-

1. Mean using Direct Method

[tex]\boxed{ \rm{ \:Mean = \dfrac{ \sum f_i x_i}{ \sum f_i} \: }} \\ \\ [/tex]

2. Mean using Short Cut Method

[tex]\boxed{ \rm{ \:Mean =A + \dfrac{ \sum f_i d_i}{ \sum f_i} \: }} \\ \\ [/tex]

3. Mean using Step Deviation Method

[tex]\boxed{ \rm{ \:Mean =A + \dfrac{ \sum f_i u_i}{ \sum f_i} \times h \: }} \\ \\ [/tex]

Answer:

Friar Laurence is presented as a holy man who is trusted and respected by the other characters. The Friar's role as the friend and advisor to Romeo and Juliet highlights the conflict between parents and their children within the play.

Explanation:

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