Please help if you can! How many possible combinations of two number cubes, numbered 1 through 6, would add up to exactly 7?​​

Answers 1

Explanation:

This is the sample outcome of cube/ dice numbered 1 through 6.

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),

(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)

(6, 1), (6, 2), (6, 3), (6, 4) , (6, 5), (6, 6)

⇒ Total number of outcomes(sample space) = 36

Getting the sum 7 (favourable outcomes) = (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1).

⇒ Probability of Getting a sum 7 = Number of favourable outcomes / Total number of outcomes.

⇒ P = 6 / 36

⇒ P = 1 / 6

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