Answer:
For you to understand better-
we can see the hints at 8 and 27 itself
8 is the cube of 2 and 27 is the cube of 3,and we can see the variable attached to them (x) is also a cube,hence we will write 8 as 2 cube and 27 as 3cube ,
2³x³ + 3³x³
since all of them are in the power of 3 we will take 3 out in a bracket
(2x)³ + (3x)³
Now we can apply sum of cubes which is
a³+b³=(a+b)(a²-ab+b²)
substituting values
(2x)³+(3x)³=(2x+3x)((2x)²-2x×3x+(3x)²)
=(2x+3x)(4x²-6x²+9x²)
=(2x+3x)(7x²)
final answer is (2x+3x)(7x²)
i hope you understand
I spent a lot of time typing this :)