Answer:
[tex]\frac{32\sqrt{x} }{x}[/tex]
Step-by-step explanation:
⇒ [tex]y = 4^{3}\sqrt{x}[/tex]
⇒ [tex]y = 64\sqrt{x} = 64x^{1/2}[/tex]
On differentiation:
⇒ [tex]\frac{dy}{dx} = 64(\frac{1}{2} )x^{1/2-1}[/tex]
⇒ [tex]\frac{dy}{dx} = \frac{32}{\sqrt{x} } = \frac{32\sqrt{x} }{x}[/tex]