Fill in the blanks with a, an or the wherever appropriate. 7. Sandeep's train was late by____ hour.​

Answer:

1008

Step-by-step explanation:

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2 | 16  

2 | 8

2 | 4

2 | 2

2 | 1

2 | 42

3 | 21

7 | 7   | 1

2 | 72

2 | 36

2 | 18

3 |  9

3 | 3

  | 1

16 = 2 x 2 x 2 x 2

42 = 2 x 3 x 7

72 = 2 x 2 x 2 x 3 x 3

HCF = 2

Step-by-step explanation:

Consider,

[tex]\qquad\sf \: {tan}^{2}A - {sin}^{2}A \\ \\ [/tex]

can be rewritten as

[tex]\qquad\sf \: = \: \dfrac{ {sin}^{2} A}{ {cos}^{2} A} - {sin}^{2}A \\ \\ [/tex]

[tex]\qquad\sf \: = \:\left( \dfrac{1}{ {cos}^{2} A} - 1\right) {sin}^{2}A \\ \\ [/tex]

[tex]\qquad\sf \: = \:\left( {sec}^{2}A - 1\right) {sin}^{2}A \\ \\ [/tex]

[tex]\qquad\sf \: = \: ({tan}^{2}A ) {sin}^{2}A \\ \\ [/tex]

[tex]\qquad\sf \: = \: {tan}^{2}A \: {sin}^{2}A \\ \\ [/tex]

Hence,

[tex]\qquad\sf\implies \bf \: {tan}^{2}A - {sin}^{2}A = {tan}^{2}A \: {sin}^{2}A \\ \\ [/tex]

[tex]\rule{190pt}{2pt}[/tex]

Formulae Used

[tex]\sf \:tanx \: = \: \dfrac{sinx}{cosx} \\ \\ [/tex]

[tex]\sf \:secx \: = \: \dfrac{1}{cosx} \\ \\ [/tex]

[tex]\sf \: {sec}^{2}x - {tan}^{2}x = 1 \\ \\ [/tex]

[tex]\rule{190pt}{2pt}[/tex]

Additional Information

[tex]\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{\pmb{{More \: Formulae}}}} \\ \\ \bigstar \: \bf{sinx = \dfrac{1}{cosecx} }\\ \\ \bigstar \: \bf{cosx = \dfrac{1}{secx} }\\ \\ \bigstar \: \bf{tanx = \dfrac{sinx}{cosx} = \dfrac{1}{cotx} }\\ \\ \bigstar \: \bf{cot x= \dfrac{cosx}{sinx} = \dfrac{1}{tanx} }\\ \\ \bigstar \: \bf{cosec x) = \dfrac{1}{sinx} }\\ \\ \bigstar \: \bf{secx = \dfrac{1}{cosx} }\\ \\ \bigstar \: \bf{ {sin}^{2}x + {cos}^{2}x = 1 } \\ \\ \bigstar \: \bf{ {sec}^{2}x - {tan}^{2}x = 1 }\\ \\ \bigstar \: \bf{ {cosec}^{2}x - {cot}^{2}x = 1 } \: \end{array} }}\end{gathered}\end{gathered}\end{gathered}[/tex]

Answer:

indirect speech of now is Then

Answer:

indirect speech of now is then