He said "I saw a movie today in reported​

Answer:

Let, AB be the line segment

Assume that points P and Q are the two different mid points of AB.

Now,

∴ P and Q are midpoints of AB.

Therefore,

AP = PB and AQ = QB.

also,

PB+AP = AB (as it coincides with line segment AB)

Similarly, QB+AQ = AB.

Now,

Adding AP to the L.H.S and R.H.S of the equation AP = PB

We get, AP+AP = PB+AP (If equals are added to equals, the wholes are equal.)

⇒ 2AP = AB — (i)

Similarly,

2 AQ = AB — (ii)

From (i) and (ii), Since R.H.S are same, we equate the L.H.S

2 AP = 2 AQ (Things which are equal to the same thing are equal to one another.)

⇒ AP = AQ (Things which are double of the same things are equal to one another.)

Thus, we conclude that P and Q are the same points.

This contradicts our assumption that P and Q are two different mid points of AB.

Thus, it is proved that every line segment has one and only one mid-point.

Hence Proved.

Answer:

I have received the information at this very moment.

Ram and Laxman left at the same time.

It started raining without any warning.

Explanation:

Answer:

1: Canis lupus familiaris

2: Equus caballus

3: Gorilla

4: panthera tigris

5: panthera leo

6: Psitaciformes

7: Lacertilia

8: culicidae

9: Gallus gallus domesticus

10: homo sapiens

Answer:

In a plane, given a line and a point not on it, at most one line parallel to the given line can be drawn through the point. It is equivalent to Euclid's parallel postulate in the context of Euclidean geometry and was named after the Scottish mathematician John Playfair.

Answer:

In a plane, given a line and a point not on it, at most one line parallel to the given line can be drawn through the point. It is equivalent to Euclid's parallel postulate in the context of Euclidean geometry and was named after the Scottish mathematician John Playfair.