What is the displacement ( in m) of a sprinter when he covers exactly half of a circular track of radius 30 m ?
Answers 1
The displacement (in m) is: c. 60
Explanation:
Displacement: Displacement is the shortest distance between initial and final position. Displacement is a vector quantity. The SI unit of displacement is m/s.
Solution: The sprinter is moving on a circular track. The radius of the circular track = 30 m.
When he covers half of the circular track, then covered distance
= \frac{1}{2} \times
2
1
× circumference of the circle = π × 30 = 30π m.
But, Displacement = shortest distance. Here the shortest distance will be the diameter of the circle.
Diameter = 2 × radius = 2 × 30 m = 60m
∴ Displacement of the sprinter is 60 m.
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