Children understand and explore the nuance of language when they ?

Answer:

Option (B)

Step-by-step explanation:

Who derived the formula for solving the quadratic equation ax²+bx+c = 0 ,where a≠0 ?

The standard quadratic equation is ax²+bx+c = 0

On dividing by a both sides then

=> (ax²+bx+c)/a = 0/a

=> (ax²/a)+(bx/a)+(c/a) = 0

=> x² +(bx/a) + (c/a) = 0

=> x²+(2/2)(bx/a) +(c/a) = 0

=> x²+(2bx/2a) +(c/a) = 0

=> x²+2(bx/2a) + (c/a) = 0

=> x² +2(b/2a)x = -c/a

=> x²+2x(b/2a) = -c/a

On adding (b/2a)² both sides then

=> x²+2x(b/2a)+(b/2a)² = (-c/a)+(b/2a)²

=> [x+(b/2a)]² = (-c/a)+(b²/4a²)

Since, (a+b)² = a²+2ab+b²

=> [x+(b/2a)]² = (-4ac+b²)/(4a²)

=> [x+(b/2a)]² = (b²-4ac)/(4a²)

=> x+(b/2a) = ±√[(b²-4ac)/(4a²)]

=> x+(b/2a) = ±[{√(b²-4ac)}/(2a)]

=> x = ±[{√(b²-4ac)}/(2a)] -(b/2a)

=> x = ±[{√(b²-4ac)}-b]/(2a)

=> x = [-b±√(b²-4ac)]/(2a)

Therefore, the roots are

[-b+√(b²-4ac)]/(2a) and [-b-√(b²-4ac)]/(2a).

This formula is known as Quadratic Formula .

This is derived by Indian Mathematician Sridharacharya.

Step-by-step explanation:

Answer:

Option (B)

Step-by-step explanation:

Corrected Question:-

Who derived the formula for solving the quadratic equation ax²+bx+c = 0 ,where a≠0 ?

Proof :-

The standard quadratic equation is ax²+bx+c = 0

On dividing by a both sides then

=> (ax²+bx+c)/a = 0/a

=> (ax²/a)+(bx/a)+(c/a) = 0

=> x² +(bx/a) + (c/a) = 0

=> x²+(2/2)(bx/a) +(c/a) = 0

=> x²+(2bx/2a) +(c/a) = 0

=> x²+2(bx/2a) + (c/a) = 0

=> x² +2(b/2a)x = -c/a

=> x²+2x(b/2a) = -c/a

On adding (b/2a)² both sides then

=> x²+2x(b/2a)+(b/2a)² = (-c/a)+(b/2a)²

=> [x+(b/2a)]² = (-c/a)+(b²/4a²)

Since, (a+b)² = a²+2ab+b²

=> [x+(b/2a)]² = (-4ac+b²)/(4a²)

=> [x+(b/2a)]² = (b²-4ac)/(4a²)

=> x+(b/2a) = ±√[(b²-4ac)/(4a²)]

=> x+(b/2a) = ±[{√(b²-4ac)}/(2a)]

=> x = ±[{√(b²-4ac)}/(2a)] -(b/2a)

=> x = ±[{√(b²-4ac)}-b]/(2a)

=> x = [-b±√(b²-4ac)]/(2a)

Therefore, the roots are

[-b+√(b²-4ac)]/(2a) and [-b-√(b²-4ac)]/(2a).

This formula is known as Quadratic Formula .

This is derived by Indian Mathematician Sridharacharya.

[tex]answer}[/tex]

Answer:

1. take boiling tube and add copper sulphate crystals to it.
2. add some water to it.
3. heat it with the burner.

Answer:

The main use of crystallization in the organic chemistry laboratory is for purification of impure solids: either reagents that have degraded over time, or impure solid products from a chemical reaction

The apparatus required : filtering the mixture - conical flask, filter paper and filter funnel. heating the solution - water bath (beaker of water on a tripod and gauze, heated over a Bunsen burner) and evaporating basin. crystallisation - watch glass.

RESULT:-

Crystallisation process results in a physical change in objects. It leads to the formation of crystal structures. Clear distinguish between processes of crystallisation is not possible. But we can identify two categories of crystallisation processes namely Cooling Crystallisation and Evaporative Crystallisation.

Answer:

H20 mass27

Molecular weight 18

Explanation:

Mole =mass/weight

=27/18

1.5 mol

Molecules=nNa

1.5×6.023×10^23

=9×10^23

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