Sir Can you please tell me where to come sir

Answer:

At 127° with river flow

Hope this will help you...

The speed of the swimmer is (u) = 0.6 m/s

The width of the river = 50 m

The speed of the water current is (v) = 0.36 m/s

She wants to reach on the other bank at a point directly opposite from her starting point, so the drift is = 0 m

Suppose she has to swim at an angle of θ with the river flow.

Now, u Cosθ = - v

⇒ Cosθ = - v/u

⇒ Cosθ = - 0.36/0.6

⇒ Cosθ = - 3/5

⇒ Cosθ = 127°

So, the direction in which she must swim is at 127° with river flow.

Answer:

1 : to deprive of strength, vigor, or spirit : weaken. 2 : to deprive of virility or procreative power : castrate. 3 : to remove the androecium of (a flower) in the process of artificial cross-pollination.

Hope it's helpful

Mark me as a Brainliest,

Emasculation refers to the process of removing the anthers from a flower. It's done before dehiscence to keep undesirable pollen out of the stigma and to ensure cross-pollination by preferred pollens.

• In artificial hybridization, emasculation is used to exclusively fertilise stigma with emasculated pollens.
• In artificial hybridisation programmes, emasculation is a technique that is used.
• Emasculation is the process of removing anthers from a flower bud with forceps before it dehisces.
• To avoid self-pollination, plant breeders use this strategy. This is useful in artificial hybridization when specific pollen is required.

Answer:

2520

Step-by-step explanation:

2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder. What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20?

To find: The smallest number that can be divided by each of the numbers from 1 to 20 without any remainder.

• We just need to take L.C.M. the smallest number that can be divided by each of the numbers from 1 to 20 without any remainder.

• The Least Common Multiple (LCM) is also referred to as the Lowest Common Multiple (LCM) and Least Common Divisor (LCD). For two integers a and b, denoted LCM(a,b), the LCM is the smallest positive integer that is evenly divisible by both a and b. For example, LCM (2,3) = 6 and LCM (6,10) = 30.

• The LCM of two or more numbers is the smallest number that is evenly divisible by all numbers in the set.

Let's do this in listing factors method.

Write down factoriaztion of each number:

1 = 1

2 = 2

3 = 3

4 = 2 * 2

5 = 5

6 = 2 * 3

7 = 7

8 = 2 * 2 * 2

9 = 3 * 3

10 = 2 * 5

11 = 11

12 = 3 * 2 * 2

13 = 13

14 = 2 * 7

15 = 3 * 5

16 = 2 * 2 * 2 * 2

17 = 17

18 = 2 * 3 * 3

19 = 19

20 = 2 * 2 * 5

Write the primes vertically. (As in attachment 1)

Bring down numbers in each column and multiply to get LCM. (As in attachment 2)

Answer:

MyQuestionIcon

Question

If the original size of an image is

540

×

680

, which of the following image sizes cannot be achieved to ensure there is no deformation in the picture?

A

135 times 170

B

27 times 34

C

1080 times 1360

D

123 times 164

Solution

The correct option is D

123 times 164

To solve this question, we need to check how

540

×

680

can be reduced or expressed as higher fractions without changing the value of this ratio. To do this, recall that ratios are mathematically, just fractions. So, let us jump into fractions.

Dividing the numerator and denominator of the original fraction with the same number won't change the value of the fraction. Dividing with

4

, we get,

(

540

÷

4

)

/

(

680

÷

4

)

=

135

/

170

.

Similarly, dividing this fraction with

5

(on numerator and denominator) would result in

27

/

34

.

Our original fraction is

540

/

680

. Multiplying the numerator and the denominator of the fraction with a same number would not change the value of this fraction. Multiplying with

2

, we get,

(

540

×

2

)

/

(

680

×

2

)

=

1080

/

1360

Going in a similar way, we observe that the original fraction cannot be written as

123

/

164

and hence this picture size cannot be achieved without compromising the picture quality.

Step-by-step explanation:

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