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Answer :

A body is dropped from a height of 100m, calculate the time it takes to hit the ground if acceleration due to gravity is 10m/sec square?

Explanation :

A body is dropped from a height of 20 m from the ground. Then, check which of the following options are correct. (g=10m/s2)

A body is dropped from a height of 20 m from the ground. Then, check which of the following options are correct. (g=10m/s2)A. the time taken by the body in reaching the ground is 2 s

A body is dropped from a height of 20 m from the ground. Then, check which of the following options are correct. (g=10m/s2)A. the time taken by the body in reaching the ground is 2 sB. the time taken by the body in reaching the ground is 4 s

A body is dropped from a height of 20 m from the ground. Then, check which of the following options are correct. (g=10m/s2)A. the time taken by the body in reaching the ground is 2 sB. the time taken by the body in reaching the ground is 4 sC. the velocity of the body on reaching the ground is 20 m/s

A body is dropped from a height of 20 m from the ground. Then, check which of the following options are correct. (g=10m/s2)A. the time taken by the body in reaching the ground is 2 sB. the time taken by the body in reaching the ground is 4 sC. the velocity of the body on reaching the ground is 20 m/sD. the velocity of the body on reaching the ground is 40 m/s

See The Attachment,

Given,

Equation,

3x² - 2x - 3 = 0

To find,

Solution using the quadratic formula.

Solution,

Using the quadratic formula, the solution to a given quadratic equation or roots of the equation can be found. Suppose the quadratic equation is,

ax² + bx + c = 0,

Then its solution or roots will be given by the formula,

[tex]x_{1,2}=\frac{-b\pm \sqrt{b^{2} -4ac} }{2a}[/tex]

Here, the given equation is,

3x² - 2x - 3 = 0

So,

a = 3,

b = -2, and,

c = -3.

Substituting these values in the above formula,

[tex]x_{1,2}=\frac{-(-2)\pm \sqrt{(-2)^{2} -4(3)(-3)} }{2(3)}[/tex]

⇒ [tex]x_{1,2}=\frac{2\pm \sqrt{(4) +36} }{6}[/tex]

⇒ [tex]x_{1,2}=\frac{2\pm \sqrt{40} }{6}[/tex]

⇒ [tex]x_{1,2}=\frac{2\pm 2\sqrt{10} }{6}[/tex]

⇒ [tex]x_{1,2}=\frac{1\pm \sqrt{10} }{3}[/tex]

⇒ [tex]x_{1}=\frac{1 + \sqrt{10} }{3},x_{2}=\frac{1 - \sqrt{10} }{3},[/tex]

Therefore, the solution of the given equations using quadratic formula will be [tex]x_{1}=\frac{1 + \sqrt{10} }{3},x_{2}=\frac{1 - \sqrt{10} }{3}.[/tex]

Answer:

NOW3

Explanation:

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Answer:

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Answer:

mean = means

on = of

includes = include

that = which

to = of

there is 'and' in wrong place = in it prayer , meditation , vocal prayers etc

the = in

are = is

Explanation:

I

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