Prefix for disciplinary

Answer:

pV=nRT or pV=

M

w

RT or M=

V

w

p

RT

or M=d

p

RT

Here, d=1.964g/dm

3

=1.964×10

−3

g/cc

P = 76 cm = 760 mm Hg = 1 atm

R = 0.0821 L atm K

−1

mol

−1

=82.1 cc atmK

−1

mol

−1

T=273K

∴M=

1

1.964×10

−3

×82.1×273

=44

The molecular weight of CO

2

is 44.

So, the gas is CO

2

.

Answer:

The molar mass of the gas is 6758 g/mol.

Given:

Density of gas, ρ = 94 mg/cc = 0.094 g/cc

Temperature, T = 15°C = 15+273 = 288 K

Pressure, P = 250 mm of Hg = 250/760 atm = 0.3289 atm

Find:

Molar mass of gas.

Solution:

According to Ideal gas equation, we have

PV = nRT             ------------------- (i)

where P = Pressure of gas

V = Volume of gas

n =Number of moles of gas

R = Universal gas constant = 0.0821 L atm K⁻¹mol⁻¹ = 82.1 cc atmK⁻¹mol⁻¹

T = Temperature of gas

Now, Number of moles of the gas = m/M

where m = mass in gram

M = Molar mass of the gas

Putting the value of n in equation (i), we get

[tex]PV = \frac{m}{M} RT[/tex]

[tex]PM=\frac{m}{V} RT[/tex]

But m/V = Density of gas, ρ

[tex]PM = \rho RT[/tex]

[tex]M = \frac{\rho RT}{P}[/tex]

Putting values in the above formula, we get

[tex]M = \frac{(0.094)(82.1)(288)}{0.3289}[/tex]

[tex]M = 6758 g/mol[/tex]

Hence, the molar mass of the gas is 6758 g/mol.

#SPJ3

Answer:

82.62

Step-by-step explanation:

THE COST OF 1 FULL TICKET =RS .27.54

COST OF 2 FULL TICKET = RS 27.52×2 = RS.55.08

AGAIN THE COST OF 1 FULL TICKET

THE COST OF 2 HALF TICKET

=RS.27.54

=RS 55.08 + 27.54

= RS 82.62

Explanation:

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Answer:

Explanation:

Clean your hands before you put your mask on, as well as before and after you take it off, and after you touch it at any time.

Make sure it covers both your nose, mouth and chin.

When you take off a mask, store it in a clean plastic bag, and every day either wash it if it’s a fabric mask, or dispose of a medical mask in a trash bin.

Don’t use masks with valves.