Answer:
Therefore, the oxidation state of Sulphur in SO2 is +4.
Explaination:
(i) SO2
Oxidation state of S + (2 × Oxidation state of O) = 0
x + (2 × -2) = 0
x – 4 = 0
x = +4
Therefore, the oxidation state of Sulphur in SO2 is +4.
(ii) PbS
Oxidation state of Pb + Oxidation state of S = 0
+2 + x = 0
x = -2
Therefore, the oxidation state of Sulphur in PbS is -2.