Distinguish between discrete series and continuous series.​

Answer:

c option is the right answer

Answer:

Heya!!

Here's your answer..

Option d)

Explanation:

तुम परदे का महत्व ही नहीं जानते, हम परदे पर कुर्बान हो रहे हैं! कहकर लेखक ने स्वयं पर व्यंग्य किया है।

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Answer:

Esters are a functional group commonly encountered in organic chemistry. They are characterized by a carbon bound to three other atoms: a single bond to a carbon, a double bond to an oxygen, and a single bond to an oxygen. The singly bound oxygen is bound to another carbon.

Answer:

RCOOR

Explanation:

C single bond R

C single bond OR

C double bond O

Answer:

Kisa Gotami was in deep grief at the loss her only son.

She wanted to get back her son, so she asked for medicines to her neighbours to treat her dead son.

Gautama Buddha asked her to bring some whether mustard seeds from a house where no one had ever died.

She went house to house in search of mustard seeds and asked everyone a family member had ever died or not.

She couldn't find any such house where no one had ever died.

Buddha taught her that everyone who has taken birth has to die someday

Explanation:

Answer: Buddha told Kisa Gotami to bring mustard seeds from a house where no one has ever died. ... Death comes to every family. Human life is filled with suffering and each person must overcome them.

Answer:

Rewrite the given equation as x2y – xy2 – xy + y2 + x – y = 0 as yx2 + (1 – x)y2 – xy + x – y = 0 Clearly asymptotes parallel to X-axis and Y-axis are y = 0 and x = 1 respectively. For oblique asymptotes: φ3(m) = m – m2 and φ2(m) = –m + m2 implying φ'3(m) = 1 – 2m so that c = Therefore, equation of asymptotes y = mx + c becomes y = 0 , y = x. Now the joint equation of the asymptotes, y(x – 1)(y – x) = 0 or x2y – xy2 – xy + y2 = 0 Clearly given equation of the curve, i.e. (x2y – xy2 – xy + y2 ) + (x – y) = 0 is expressible like Fn + Fn – 2 = 0 wherein we have obtained, Fn = 0, i.e. x2y – xy2 – xy + y2 = 0 as the joint equation of the asymptotes. and c = - φ2(m)/φ3(m) = - ( - 2am2)/ 2m = am = ± a Therefore the two oblique asymptotes are y = x + a and y = –x – aRead more on Sarthaks.com - https://www.sarthaks.com/495949/find-the-asymptotes-of-the-curve-x-2y-xy-2-xy-y-2-x-y-0-and-show-that-they-cut-the-curve-again