Survey helps to determine the method of collection of _ _ _ _ _​

The given problem is solved in Python.

a = input('Enter first string: ')

b = input('Enter second string: ')

combined = a + b

print('Combined string: ' + combined)

• In this program, we are asked to concatenate two strings. Concatenating string means to combine two or more strings.
• In the above program, we ask user to enter two strings. The strings are taken as input using input() function.
• Now, we will use plus operator (+) to combine the strings.
• Plus operator can be used in addition as well as in combining strings.
• The resultant string is now displayed using print() function.

Refer to the attachment for output.

Answer:

Some

Explanation:

I have some homework to do for tomorrow.

Answer:

pV=nRT or pV=

M

w

RT or M=

V

w

p

RT

or M=d

p

RT

Here, d=1.964g/dm

3

=1.964×10

−3

g/cc

P = 76 cm = 760 mm Hg = 1 atm

R = 0.0821 L atm K

−1

mol

−1

=82.1 cc atmK

−1

mol

−1

T=273K

∴M=

1

1.964×10

−3

×82.1×273

=44

The molecular weight of CO

2

is 44.

So, the gas is CO

2

.

Answer:

The molar mass of the gas is 6758 g/mol.

Given:

Density of gas, ρ = 94 mg/cc = 0.094 g/cc

Temperature, T = 15°C = 15+273 = 288 K

Pressure, P = 250 mm of Hg = 250/760 atm = 0.3289 atm

Find:

Molar mass of gas.

Solution:

According to Ideal gas equation, we have

PV = nRT             ------------------- (i)

where P = Pressure of gas

V = Volume of gas

n =Number of moles of gas

R = Universal gas constant = 0.0821 L atm K⁻¹mol⁻¹ = 82.1 cc atmK⁻¹mol⁻¹

T = Temperature of gas

Now, Number of moles of the gas = m/M

where m = mass in gram

M = Molar mass of the gas

Putting the value of n in equation (i), we get

[tex]PV = \frac{m}{M} RT[/tex]

[tex]PM=\frac{m}{V} RT[/tex]

But m/V = Density of gas, ρ

[tex]PM = \rho RT[/tex]

[tex]M = \frac{\rho RT}{P}[/tex]

Putting values in the above formula, we get

[tex]M = \frac{(0.094)(82.1)(288)}{0.3289}[/tex]

[tex]M = 6758 g/mol[/tex]

Hence, the molar mass of the gas is 6758 g/mol.

#SPJ3

Answer:

82.62

Step-by-step explanation:

THE COST OF 1 FULL TICKET =RS .27.54

COST OF 2 FULL TICKET = RS 27.52×2 = RS.55.08

AGAIN THE COST OF 1 FULL TICKET

THE COST OF 2 HALF TICKET

=RS.27.54

=RS 55.08 + 27.54

= RS 82.62