what is cloud computing​

Answer:

Rent A/c Dr. 6000

Drawings A/c Dr. 6000

To Cash/Bank A/c. 12000

Explanation:

Since half the building is used by proprietor for his personal use, half of the rent will be considered as Drawings by the proprietor.

Step-by-step explanation:

Answer:

898.33cm³

Explanation:

Given :

Ratio of radius and height => 2:5.

Area of the base => 154cm²

To Find :

Volume of the cone.

Solution :

Let the radius and height of the cone be 2x and 5x respectively.

We know base area of cone = πr²

\rightarrow \sf{}154cm^2 = \pi\times r^2→154cm

2

=π×r

2

\rightarrow \sf{}154cm^2 = \dfrac{22}{7}\times2x\times2x→154cm

2

=

7

22

×2x×2x

\rightarrow \sf{}154cm^2 = \dfrac{22}{7}\times4x^2→154cm

2

=

7

22

×4x

2

\rightarrow \sf{}154cm^2 \div \dfrac{22}{7} =4x^2→154cm

2

÷

7

22

=4x

2

\rightarrow \sf{}49=4x^2→49=4x

2

\rightarrow \sf{}\dfrac{49}{4}=x^2→

4

49

=x

2

\rightarrow \sf{}\sqrt{\dfrac{49}{4}}=\sqrt{x^2}→

4

49

=

x

2

\rightarrow \sf{}x=\dfrac{7}{2}→x=

2

7

\sf{}Radius = > 2xRadius=>2x

\sf{}= > 2\bigg(\dfrac{7}{2}\bigg)=>2(

2

7

)

= > 7=>7

\sf{}Height =5xHeight=5x

\sf{}= > 5\bigg(\dfrac{7}{2}\bigg)=>5(

2

7

)

\sf{}= > \dfrac{35}{2}=>

2

35

\sf{}Volume\ of\ the\ cone = \dfrac{1}{3}\pi r^{2}hVolume of the cone=

3

1

πr

2

h

\sf{}\Rightarrow\dfrac{1}{3}\times\dfrac{22}{7}\times7^2\times\dfrac{35}{2}⇒

3

1

×

7

22

×7

2

×

2

35

\sf{}\Rightarrow\dfrac{1}{3}\times\dfrac{11}{1}\times49\times\dfrac{5}{1}⇒

3

1

×

1

11

×49×

1

5

\sf{}\Rightarrow\dfrac{11}{3}\times}245

\sf{}\Rightarrow\dfrac{2695}{3}⇒

3

2695

\sf{}\Rightarrow 898.33cm^3⇒898.33cm

3

Therefore,volume of the cone is equal to 898.33cm³

Answer:

Yes

Step-by-step explanation:

2x-7+23y=x-2y hope it will help you

Answer:

yes this is in a standard form