6. Find the equivalent capacitance if three capacitors each of 12 uf are connected in series and if they are connected in parallel. (Ans: Cs = 4uf, Cp = 36uf) ​

Answer:

Weavers dependent on cloth merchants because of the following reasons: Merchants provide raw materials to weavers. Merchants also provide much needed money to the weavers. Once the cloth is ready, merchants supply cloth to garment manufacturers.

Answer:

Hope the world map is clear to you!!

Answer:

Answer:

Do This 1. A cuboid looks like a rectangular box. It has 6 faces. Each face has 4 edges. Each face has 4 corners (called vertices). 2. A cube is a cuboid whose edges are all of equal length. t) C It has_ faces. Each face has _edges. +S Each face has_vertices. yC 3. A triangular pyramid has a triangle as its base. It is alse tetrahedron. )C Faces ：_ )P Edges ：_ Corners_:_ ve ha 4. A square pyramid has a square as its base.. Faces : _ Edges :_ Corners_: _ 2 5. A triangular prism looks like the shape of a Kaleidoscope.lie as its bases. Faces__: _ Edges__: _ Corners

Answer:

A cuboid

Explanation:

Answer:

[tex](994)^{ \frac{1}{3} } \\ \\ (1000 - 6)^{ \frac{1}{3} } \\ \\ \bigg \{1000 \bigg( 1 - \frac{6}{1000} \bigg ) \bigg \}^{ \frac{1}{3} } \\ \\ \bigg \{10 ( 1 - 0.006 ) \bigg \}^{ \frac{1}{3} } \\ \\10 \bigg ( 1 - \frac{1}{3} \times 0.006 \bigg) \\ \\ 10(1 - 0.002) \\ \\ 10(0.998) \\ \\ \bf 9.98[/tex]

Given:

(994)^1/3

To Find:

Find the value using the binomial theorem

Solution:

When the power of the algebraic expression increases it becomes lengthy to find the value like (x+3)^66 is very hard to calculate that why we use binomial theorem for the expansion of term with greater powers or fractions, a binomial expansion should only contain two not similar terms if the power of the expansion is n then the total number of terms in the expansion will be (n+1).

The formula for expansion if the power is in the fraction is,

If n is negative or fraction also |x|<1, then the expansion will be,

[tex](1+x)^n=1+nx+\frac{n(n-1)}{2!}x^2 +\frac{n(n-1)(n-2)}{3!}x^3 +...[/tex]

Now to find the value of (994)^1/3, we will go as

[tex]=(994)^{1/3}\\=(993+1)^{1/3}\\=1+\frac{993}{3}+\frac{\frac{1}{3} *\frac{-2}{3} }{2!}*993*993+\frac{\frac{1}{3}*\frac{-2}{3} *\frac{-5}{3} }{3!}*993*993*993+...\\=1+331-54780.5+60441151.67-...\\=9.97[/tex]

Hence, the value of (994)^1/3 is 9.97.