Calculate the number of moles in each of the following. (i)784 g of H2SO4 (H=1,S=32,O =16) (ii)6.022 x 10^22 molecules of oxygen (iii)16 g of calcium atoms (Ca =40)

Answer:

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Answer:

Explanation:

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Answer:

the c one 58 and 20+++++++++++-

We have 

(x,y)∈R⇔x2+y2=25

⇔y=±25−x2

We observe that x=0⇒y=±5

∴(0,5)∈R and (0,−5)∈R

x=±3⇒y=±25−9=±4

∴(3,4)∈R,(−3,4)∈R,(3,−4)∈R  and (−3,−4)∈R

x=±4⇒y=±25−16=±3

∴(4,3)∈R,(−4,3)∈R,(4,−3)∈R and (−4,−3)∈R

x=±5⇒y=±25−25=0

∴(5,0)∈R and (−5,0)∈R

We also notice that for any other integral value of x,y is not an integer.

∴R={(0,5),(0,−5),(3,4),(−3,4),(

Answer:

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Class 11

>>Applied Mathematics

>>Relations

>>Relations

>>A relation R is defined on the set z of

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A relation R is defined on the set z of integers as follows. (x,y)∈R⇔x

2

+y

2

=25. Express R and R

−1

as the set of ordered pairs and hence find their respective domains.

Medium

Solution

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We have

(x,y)∈R⇔x

2

+y

2

=25

⇔y=±

25−x

2

We observe that x=0⇒y=±5

∴(0,5)∈R and (0,−5)∈R

x=±3⇒y=±

25−9

=±4

∴(3,4)∈R,(−3,4)∈R,(3,−4)∈R and (−3,−4)∈R

x=±4⇒y=±

25−16

=±3

∴(4,3)∈R,(−4,3)∈R,(4,−3)∈R and (−4,−3)∈R

x=±5⇒y=±

25−25

=0

∴(5,0)∈R and (−5,0)∈R

We also notice that for any other integral value of x,y is not an integer.

∴R={(0,5),(0,−5),(3,4),(−3,4),(3,−4),(−3,−4),(4,3),(−4,3),(4,−3),(−4,−3),(5,0),(−5,0)}

and

R

−1

={(5,0),(−5,0),(4,3),(4,−3),(−4,3),(−4,−3),(3,4),(3,−4),(−3,4),(−3,−4),(0,5),(0,−5)}

Clearly domain [R]={0,3,−3,4,−4,5,−5}= domain(R

−1

)

Step-by-step explanation:

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Answer:

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