equivalent weight of FeC2O4​

Answers 2

Fe  

+2

→Fe  

+3

+e  

−

 

C  

2

​

O  

4

​

 

−2

→2CO  

2

​

+2e  

−

 

Adding both the reactions, we get,

Fe  

+2

+C  

2

​

O  

4

​

 

−2

→2CO  

2

​

+Fe  

+3

+3e  

−

 

Equivalent weight is defined as the molecular weight divided by the number of moles of electron required by the molecule.  

Hence, the equivalent weight is equal to  

3

M

​

.

Answer: Fe+2

→Fe+3+e−C2O4  

−2  →2CO2+2e−

Adding both the reactions, we get,

Fe  

+2

+C  

2

​

O  

4

​

 

−2

→2CO  

2

​

+Fe  

+3

+3e  

−

 

Equivalent weight is defined as the molecular weight divided by the number of moles of electron required by the molecule.  

Hence, the equivalent weight is equal to  

3

M

​

.

Explanation:

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Answer:

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Mohan bought 20 dining tables for rupees 12000 and sold them at profit equal to the selling price of 4 dining tables.The selling price of each dining yable is​

Refer to the attachment!!

answer img

Step-by-step explanation:

There are 2 times 199 in 569.

The answer you divide 569 by 199 which would get you 2.8592964824121.

The remainder is 171

In a completely dark room , if you hold up a mirror in front of you see a reflection of yourself in the mirror ?​

Answer:

No, we will not see our reflection in mirror in a dark room because an image is formed only when the light gets reflected by the mirror whereas in a dark room, there is no light to cause reflection hence, no image will be formed.

Hope this helps (:

Answer:

No

Explanation:

You won't see your reflection because there is no source of light in the room. But if you were in a completely dark room with a flashlight you would see your reflection

Two bodies begin a free fall from rest, from the same height, 1 second apart. How long after the first body begins to fall, will the two bodies be 10 m apart? (1) 25 (2) 3.5 s (3) 0.5 s [(4) 1.5 S ​

Answer:

The required time lapse is (4) 1.5 s.

Explanation:

Let , the first body fell 's' meters down in 't' seconds.

According to the question , the second body fell 's₀' meters in ( t - 1 ) seconds.

Both of them started falling from rest , so the initial velocity for both body is 0 m/s .

let , the acceleration due to gravity is g = 10 m/s²

then , s = 0 × t + ( 1/2)gt² ⇒ s = (1/2)gt²

and , s₀ = 0 × t + ( 1/2 )g( t - 1 )² ⇒ s₀ = ( 1/2 )g( t - 1 )²

According to the question ,

s₀ = s - 10

⇒  ( 1/2 )g( t - 1 )² =  (1/2)gt² - 10

⇒ ( 1/2 )g( t² - 2t + 1 ) = (1/2)gt² - 10

⇒ ( 1/2 )gt² - gt + g/2 = (1/2)gt² - 10

⇒  gt = 10 + g/2

⇒ 10t = 10 + 5

⇒ 10t = 15

⇒ t = 1.5 seconds

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