7.Polythene is prepared by process of polymerization by……?​

Given,

Distance between two cities A and B = 620 Km

Total time taken by a train traveling between A and B = 5 hours and 15 minutes

Total time spent by the train to halt at intermediate stations = 25 minutes

To find,

The approximate average speed of the train between A and B excluding the time it was stopped at other stations.

Solution,

We can simply solve this numerical problem by using the following process:

Mathematically,

speed (s) = distance traveled (d)/time taken(t)

Now,

Total time taken by the train in traveling between A and B, excluding the halting time

= Total time taken by a train traveling between A and B - Total time spent by the train to halt at intermediate stations

= (5 hours and 15 minutes) - (25 minutes)

= 4 hours 50 minutes

= 4(5/6) hours

= 29/6 hours

Now,

The approximate average speed of the train between A and B excluding the time it was stopped at other stations

= total distance traveled / total time taken by the train in traveling between A and B, excluding the halting time

= (620Km) / (29/6 hours)

= 128.28 Km/hr

= 130 Km/hr (approximately)

Hence, the approximate average speed of the train between A and B excluding the time it was stopped at other stations is equal to 130 Km/hr.

Answer:

7920

Step-by-step explanation:

11*2=22,22*3=66,66*4=264,264*5=1320,1320*6=7920

Answer:

1683

Step-by-step explanation:

11 +22+66+264 +1320=1683

Let x be distance between Rajesh’s home and office.

Distance travelled by Rajesh is given as –

x = 4x/5 + 3x/20 + 1

x – 4x/5 – 3x/20 = 1

x/20 = 1

x = 20 km

Therefore, distance between home and office of Rajesh is 20 km.

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Explanation:

MV = mv

law of conservarion of momentum

30*200=3000*x

x=20