Given: Two rings of radius r and nr
To find: Ratio of their Moment of Inertia
Solution:
The moment of inertia of a ring about an axis perpendicular to the plane and passing through the center is given by: MR².
Here,
M=Mass
R=Radius
Moment of Inertia (MI) of a ring of r radius = Mr² --------(i)
Moment of Inertia (MI) of a ring of r radius= M(nr)² = Mn²r² -------(ii)
On dividing (i) by (ii)
The ratio comes out to be:
Mr²/ Mn²r² = 1/n²