A system absorbs 500kJ heat and performs 250kJ work on the surroundings .The increase in internal energy of the system is?
Answers 2
Answer:
q=500 kJ (as heat is absorbed, so it is positive)
w=−250 kJ (as work is done by the system, so it is negative)
∴ΔU=q+w=50−20=250kJ
Therefore, internal energy change increases by 250 kJ.
Explanation:
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Author:
mikokhan
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Concept Introduction:
Internal drive U is the sum of the kinetic energy brought about by the motion of molecules and the potential energy brought about by the vibrational motion and electric energy of atoms inside molecules in a system or a body with clearly defined limits. The energy contained in every chemical link is often referred to as internal energy.
Given:
System absorbs [tex]500[/tex]kJ heat and performs [tex]250[/tex]kJ work
To Find:
We have to find the value of, internal energy of the system.
Solution:
According to the problem,
q=[tex]500[/tex]kJ (as heat is absorbed, so it is positive)
w=−[tex]250[/tex] kJ (as work is done by the system, so it is negative)
∴ΔU=q+w=[tex]500[/tex] - [tex]250[/tex] =[tex]250[/tex] kJ
Final Answer:
The value of increase in internal energy of the system is [tex]250[/tex] kJ.
SPJ2
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Author:
duchessvazquez
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