(25 )Which statement is incorrect about complexes formed by the lanthanides? A.Hard donor ligands are favoured B.High coordination numbers are observed C.The 4f atomic orbitals do not play role bonding D.Aqua ions are typically 6-coordinate​

Answer:

b option ok opyion b HPO42

Phosphorus uptake in alkali soil in the form of D) H3PO4.

• The plant absorbs phosphorus in the form of ortho phosphorous(H3PO4). and absorb it through the roots by the process of diffusion.
• In alkaline and acidic soil, phosphate is not taken up by plants because in acidic soil it gets reacted with iron and aluminium while in alkaline it is reacted with calcium hence, inapproachable for plants.
• Phosphorous is present in the earth's crust and not in gaseous form.
• Phosphorous in plants is broken down by microorganisms microorganisms

Answer:

BrF5 is the correct answer

Answer:

please mark me as brainliest and follow

Answer:

385cm^3

Step-by-step explanation:

Volume of cone = (1/3)πr^2h

                            = 1/3 * 22/7 * 7 * 7 * 12

                            = 616cm^3

Volume of Cylinder = πr^2h

                                  = 22/7 * 7/2 * 7/2 * 6

                                  = 231cm^3

Therefore,

Remaining = Volume of cone - Volume of cylinder

                   = 616 - 231

                   = 385cm^3

Hope it is clear!

Do marks as brainliest!

Answer:

Remaining piece of wood 385 cm³

Step-by-step explanation:        

Given data

A cylinder is drilled out from a wooden cone

The radius and height of the cylinder is equals to half that of the cone

Dimensions of cone are

⇒ Radius OP = 7 cm , ⇒  Height OQ = 12 cm  

⇒ then volume of cone = [tex]\frac{1}{3} \pi r^{2} h[/tex] =  [tex]\frac{1}{3}[/tex] × [tex]\frac{22}{7}[/tex] × 7 × 7 ×12 =

                                                    = 22 × 7 × 4 = 616 cm³

Dimensions of cylinder are  

⇒ half of that of the cone

⇒ radius of cylinder r = 7/2 = 3.5 cm    

⇒ height of cylinder h = 12/2 = 6 cm

⇒ volume of the cylinder =  [tex]\pi r^{2} h[/tex] = [tex]\frac{22}{7}[/tex] × 3.5 × 3.5 × 6

                                                      = 22 × 3.5 × 3 = 231 cm³  

here we need to find the remaining piece of wood

⇒ Remaining piece of wood = volume of cone - volume of cylinder

                                                = 616 cm³  -  231 cm³    

                                               = 385 cm³