Calculate the mass of 100 molecules of copper carbonate. [Atomic mass of Cu = 63.5 u]​

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Answer:

nswer

1 mole of CuSO4 contains 1 mole of copper.

Molar mass of CuSO4 = atomic mass of Cu + atomic mass of S + 4X atomic mass of O

Molar mass of CuSO4 = (63.5) + (32.00) + 4(16.00)

= 63.5 + 32.00 + 64.00 = 159.5 amu

Gram molecular mass of CuSO4= 159.5 g

159.5 g of CuSO4 contains Cu = 63.5

1 g of CuSO4 contains Cu= 63.5/159.5* 1

Therefore 100g of CuSO4 contains Cu = 63.5/159.5*100 = 39.81 g

Explanation:

1 mole of CuSO4 contains 1 mole of copper.

Molar mass of CuSO4 = atomic mass of Cu + atomic mass of S + 4X atomic mass of O

Molar mass of CuSO4 = (63.5) + (32.00) + 4(16.00)

= 63.5 + 32.00 + 64.00 = 159.5 amu

Gram molecular mass of CuSO4= 159.5 g

159.5 g of CuSO4 contains Cu = 63.5

1 g of CuSO4 contains Cu= 63.5/159.5* 1

Therefore 100g of CuSO4 contains Cu = 63.5/159.5*100 = 39.81 g

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