3. Which of the following possess highest bond length? 1) CHF 2) CH3C1 3) CH3Br 4) CH3​

Explanation:

आसमान में जैसे-जैसे रंग बदलते दिखाई दिए हैं वैसे-वैसे गाँव के घर में भी प्रकट हुए हैं। वहाँ भी सिल है, राख से लीपा हुआ चौका है, स्लेट की कालिमा है और रंग-बिरंगे चॉक को थामनेवाले अदृश्य हाथ भी हैं।

Answer:

To determine the height of the tree, you can use the mirror as shown in Figure 72. The FD ray of light, reflecting at point D, falls on the viewer's eye (at point B). Determine the height of the tree if AC = 165 cm, BC = 12 cm, AD = 120 cm, DE = 4, 8uI angle1 = angle2.

Answer:

Vertical Letter Arrangement. The jumbled letters can be placed vertically one after another, just like a column of letters.

Horizontal Letter Arrangement. On the other hand, the letters of a scrambled word can be present horizontally. ...

Triangular Letter Arrangement.

Answer:

Swami laid his bed under a bench in the office room because he was very scared. Everyday he used to sleep beside his granny but that day he had to sleep alone. His father wants him to become brave not coward.

Explanation:

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Answer:

It is given that the median is 28.5. So, the median lies in the group of 30 – 40. Hence, the value of x and y is 8 and 7 respectively.

Answer:

Here, it is given that Median =28.5 and n=∑fi=60Cummulative frequency table for the following data is given.Here n=60⇒ 2n=30Since, median is 28.5, median class is 20−30Hence, l=20,h=10,f=20,c.f.=5+x

Here, it is given that Median =28.5 and n=∑fi=60Cummulative frequency table for the following data is given.Here n=60⇒ 2n=30Since, median is 28.5, median class is 20−30Hence, l=20,h=10,f=20,c.f.=5+xTherefore, Median =l+(

f2n −cf )h28.5=20+( 2030−5−x)10

−cf )h28.5=20+( 2030−5−x)10⇒28.5=20+

−cf )h28.5=20+( 2030−5−x)10⇒28.5=20+ 225−x

⇒8.5×2=25−x

⇒8.5×2=25−x⇒x=8

⇒8.5×2=25−x⇒x=8Also, 45+x+y=60

⇒8.5×2=25−x⇒x=8Also, 45+x+y=60⇒y=60−45−x=15−8=7.

Step-by-step explanation:

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