Answer:
First Case (Room),
Length (L) of a floor = 6.5m
Breadth (B) of a floor = 5m
Therefore,
Area of a floor = L × B
= 6.5 × 5 sq. m
= 32.5 sq. m
= 32.5 × 100 × 100 sq. cm
= 325000 sq. cm
Second case (tiles),
Side of a square tile = 25 cm
Therefore,
Area of a square tile = (side)^2
= (25)^2 sq. cm
= 625 sq. cm
Therefore,
No. of tiles required = 325000/625
= 520
Cost of 1 tile = ₹ 9.40 (given)
Therefore,
Cost of 520 tiles = ₹ (520×9.40)
= ₹ 4888 (ans.)
Answer :- The cost of flooring a room 6.5m by 5m with square tiles of side 25 cm at the rate of ₹ 9.40 per tile is ₹ 4888.