1. Write the relation between Kc and Kp for the reaction PCl5 (g) ⇌ PCl3 (g) + Cl2 (g) correct answers gets the brainliest​

Answers 2

Exρlαnαtion :

Given to write the relation between the Kp and Kc . We have the relation of kp and kc by using that and given information finding the value of "n" then we can get the relation between them .So, Let's do ..

[tex] \: \: \: \: \: \: \: \: \: \boxed{ \sf \: \: k_p \: = k_c \:(RT) {}^{ \triangle \: n} } \bigstar[/tex]

Considering the reaction,

[tex] \sf \: PCl_5 \: (g) \: \ \leftrightharpoons \: PCl_3 (g)+ Cl_2(g)[/tex]

[tex] \sf \: \triangle \: n = (1 + 1) - 1[/tex]

[tex] \sf \: \triangle \: n = 2 - 1[/tex]

[tex] \sf \: \triangle \: n = 1[/tex]

Now, Substituting △n in the relation we have :

[tex] \: \: \: \: \: \: \: \: \: \boxed{ \sf \: \: k_p \: = k_c \:(RT) {}^{ \triangle \: n} } \bigstar[/tex]

[tex] \sf \: \: k_p \: = k_c \:(RT) {}^{ 1}[/tex]

[tex] \: \: \boxed{ \sf \large\orange{\: \: k_p \: = k_c \:(RT)} }[/tex]

So, the Relation between Kp and Kc of the given reaction is Kp= Kc(RT).

Note : While taking value of "n" only gaseous state is considered not where as solids ,gaseous ,aqueous are not to be considered.

Answer:

KP > KC

Explanation:

PCl5(g) ⇋ PCl3(g) + Cl2(g)  

KP = KC(RT)∆n

∆n = nP – nR = 2 – 1 = 1

∆n = +Ve

∴ KP > KC

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