At a certain temperature 2HI H2 + I2 only 50 a.0.25 b.0.3 c.0.5 d.1

Answers 2

Answer:

c is the correct answer of what is asking

Explanation:

Correct option is A)

2HI⇔H2 +I2

2 0 0 Initial concentration

2-2x x x At equilibrium

Since only 50% of HI is dissociated, thus

2x=1=>x=0.5

Now, from expression for equilibrium constant for the reaction we get,

Kc = x²/2–2x

=0.25

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