A double riveted double cover butt joint in plates 25 mm thick with 30 mm diameter rivets at 100 mm pitch. The permissible stress in tension, shear and crushing are 120 MPa, 100 MPa and 150 MPa respectively. What is the efficiency of joint, taking the strength of rivet in double shear as twice that of single shear? 70% 60% 50 % 68%
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Subject:
CBSE BOARD X -
Author:
corneliusdavies -
Created:
1 year ago
Answers 1
Answer:
70%
Explanation:
The correct option is A 70%
1. Shearing resistance of rivets per pitch length,
Pa=2×n×π/4×[tex]d^{2}[/tex]×τs
n = Numbr of rivets per pitch length
for double riveted joint,
n = 2
Ps=2×2×π/4×[tex]30^{2}[/tex]×100
=282743.33
N=282.74kN
2. Crushing strength per pitch length,
Pc=n×d×t×σc
=2×30×25×150
=225000
N= 225 kN
3. Tearing resistance of the plate per pitch length
Pt=(p−d)×t×σt
=(100−30)×25×120
=210000
N= 210 kN
Strength of solid plate
= p×t×σt
=100×25×120
= 30000 = 300 kN
ηjoint=210/300
=0.7
=70%
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Author:
santosne7h
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